Question...Does anyone know the conditions that are required to achieve the maximum HHO flow rate with the least amount of power used?? May be stated as Liters per time per Watt. I would hate to do the test matrix myself if someone else has done this already.
Admin/Mentor
Thats the million dollar question for sure. What is the optimum cell configuration. One that allows for minimum power and produces maximum HHO. The person who figures it out could be a rich man.
2006 Ram, 5.9 cummins HO. 4 cell design, 1.5 LPM@30amp, 24.3 MPG
I can figure it out and build the setups required but I do not have the resources($$$).
Welcome and joint the club....we have all been trying to figure that one out for a long time!
To me, it sound pretty simple to find out. I just do not have the time and money.
Like I said....join the club!
I am new to this forum but been playing with HHO for a few months. It looks as if this thread is dead so hopefuly I am not stepping on feet here. My newest generator's efficency is 200watts per liter minute (WpLM). This is an easy figure to arive at if you know your amps, volts and production. I have been trying to compare efficeicy and see how I am doing in comparison to the rest of the world (right page wrong page). I have seen some units rate at over 800 WpLM and some claim 50 WpLM (I doubt that). Will anyone share their results?
Walt
I'm not familiar with watts per liter minute (WpLM). I am familiar with liters per minute per watt(and milliliters per minute per watt).Originally Posted by Walt
How is WpLM calculated?
It is calculated by first timing how long it takes to produce a liter. For example 1 minute and 15 seconds = (1.25 minutes) (VxA)x1.25=WpLM Eg. (12vX18A=216Watts)X1.25=270WpLM
A higher producing unit at the same watt load would look like this 1 liter in 45 seconds (.75 minutes) would be (12v18a)X.75=162 Otherwize the second model uses less juce for the same HHO 162 is better than 270.
The key is produce and time 1 liter. Take the number of seconds and divide that by 60 to get the decimalized minute fraction.
Anyhew
From your own example "Eg. (12vX18A=216Watts)X1.25=270WpLM"
Wouldn'd this be considered Watt*Liter*Minutes or just Watt*Minutes? The acronym "WpLM" indicates that Watts are divided by (liter*Minutes).
The problem I see with expressing electrolyzer efficiency in this manner is;
1. Faster(better) production of HHO gas yields smaller numbers. One would normally consider larger numbers to be better.
2. Since normal production values are stated as Liters per Minute(L/M), does it make sense to express electrolyzer efficiency in terms of this production per Watt? As in Liters per Minute per Watt(L/M/W) or milliliters per Minute per Watt(mL/M/W).
I am beginning to see the benefit of using milliliters per Minute per Watt(mL/M/W). This is because the numbers are large enough to be easily compared and larger number are always better.
W=V*I=volts*amps
M=minutes that it took to make the HHO sample
mL=is the volume in milliliters of the HHO sample
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